Question : The sum of the length and breadth of a rectangle is 6 cm. A square is constructed such that one of its sides is equal to a diagonal of the rectangle. If the ratio of areas of the square and rectangle is 5 : 2, the area of the square (in cm²) is:

Option 1: $20$

Option 2: $10$

Option 3: $4\sqrt{5}$

Option 4: $10\sqrt{2}$

Question : If the length of a certain rectangle is decreased by 4 cm and breadth is increased by 2 cm, it would result in a square of the same area. What is the perimeter of the original rectangle?

Option 1: 15 cm

Option 2: 24 cm

Option 3: 20 cm

Option 4: 10 cm

Question : What is the perimeter of a square inscribed in a circle of radius 5 cm?

Option 1: $20 \sqrt{2}\ \mathrm{~cm}$

Option 2: $40\sqrt{2}\ \mathrm{~cm}$

Option 3: $30\sqrt{2}\ \mathrm{~cm}$

Option 4: $10\sqrt{2}\ \mathrm{~cm}$

Question : If $\triangle A B C \sim \triangle F D E$ such that $A B=9 \mathrm{~cm}, A C=11 \mathrm{~cm}, D F=16 \mathrm{~cm}$ and $D E=12 \mathrm{~cm}$, then the length of $BC$ is:

Option 1: $5 \frac{3}{4} \mathrm{~cm}$

Option 2: $4\frac{3}{5} \mathrm{~cm}$

Option 3: $3\frac{5}{7} \mathrm{~cm}$

Option 4: $6\frac{3}{4} \mathrm{~cm}$

Question : If $\triangle ABC \sim \triangle QRP, \frac{\operatorname{area}(\triangle A B C)}{\operatorname{area}(\triangle Q R P)}=\frac{9}{4}, A B=18 \mathrm{~cm}, \mathrm{BC}=15 \mathrm{~cm}$, then the length of $\mathrm{PR}$ is:

Option 1: 16 cm

Option 2: 14 cm

Option 3: 10 cm

Option 4: 12 cm