Question : The area of the square inscribed in a circle of radius 8 cm is:
Option 1: $256\;\mathrm{cm^2}$
Option 2: $250\;\mathrm{cm^2}$
Option 3: $128\;\mathrm{cm^2}$
Option 4: $125\;\mathrm{cm^2}$
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Correct Answer: $128\;\mathrm{cm^2}$
Solution : The diagonal of the square is equal to the diameter of the circle. The diameter of this circle $= 2×8 = 16 \;\mathrm{cm}$ In a square, where the diagonal $(d)$ and the side $(s)$, $d = s\sqrt{2}$ The side of the square, $s = \frac{d}{\sqrt{2}} = \frac{16}{\sqrt{2}} = 8\sqrt{2}\;\mathrm{cm}$ $\therefore$ The area of the square inscribed in the circle $=s^2=(8\sqrt{2})^2 = 128\;\mathrm{cm^2}$ Hence, the correct answer is $128\;\mathrm{cm^2}$.
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Question : What is the perimeter of a square inscribed in a circle of radius 5 cm?
Option 1: $20 \sqrt{2}\ \mathrm{~cm}$
Option 2: $40\sqrt{2}\ \mathrm{~cm}$
Option 3: $30\sqrt{2}\ \mathrm{~cm}$
Option 4: $10\sqrt{2}\ \mathrm{~cm}$
Question : Two circles touch each other externally. The radius of the first circle with centre O is 12 cm. Radius of the second circle with centre A is 8 cm. Find the length of their common tangent BC.
Option 1: $6 \sqrt{6} \mathrm{~cm}$
Option 2: $8 \sqrt{3} \mathrm{~cm}$
Option 3: $8 \sqrt{2} \mathrm{~cm}$
Option 4: $8 \sqrt{6} \mathrm{~cm}$
Question : In an equilateral triangle of side 24 cm, a circle is inscribed touching its sides. The area of the remaining portion of the triangle is:
Option 1: $98.55\;\mathrm{cm^2}$
Option 2: $100 \;\mathrm{cm^2}$
Option 3: $101 \;\mathrm{cm^2}$
Option 4: $95\;\mathrm{cm^2}$
Question : The radius of a circle with centre at O is 6 cm and the central angle of a sector is 40°. Find the area of the sector.
Option 1: $6 \pi ~\mathrm{cm}^2$
Option 2: $5 \pi ~\mathrm{cm}^2$
Option 3: $4 \pi ~\mathrm{cm}^2$
Option 4: $8 \pi ~\mathrm{cm}^2$
Question : The area of a sector of a circle is 88 sq. cm., and the angle of the sector is 45°. Find the radius of the circle. (Use $\pi=\frac{22}{7}$)
Option 1: $3 \sqrt{ 11} \mathrm{~cm}$
Option 2: $4 \sqrt{ 14} \mathrm{~cm}$
Option 3: $6 \sqrt{ 13} \mathrm{~cm}$
Option 4: $5 \sqrt{ 14} \mathrm{~cm}$
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