Question : The area of triangle with vertices A(0, 8), O(0, 0), and B(5, 0) is:
Option 1: 8 sq. units
Option 2: 13 sq. units
Option 3: 20 sq. units
Option 4: 40 sq. units
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Correct Answer: 20 sq. units
Solution : Let (x1, y1) = (0, 8) (x2, y2) = (0, 0) (x3, y3) = (5, 0) Area of a triangle with vertices (x1, y1), (x2, y2), and (x3, y3) = $\frac{1}{2}$ [x1 (y2 – y3) + x2 (y3 – y1) + x3 (y1 – y2)] = $\frac{1}{2}$ [0(0 – 0) + 0(0 – 8) + 5(8 – 0)] = $\frac{1}{2}$[40] = 20 sq. units Hence, the correct answer is 20 sq. units.
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Question : The area of the triangle formed by the graph of the straight lines $x-y=0$, $x+y=2$, and the $x$-axis is:
Option 1: 1 sq. unit
Option 2: 2 sq. units
Option 3: 4 sq. units
Option 4: 5 sq. units
Question : What is the area (in sq. units) of the triangle formed by the graphs of the equations $2x + 5y - 12=0, x + y = 3,$ and $y = 0$?
Option 1: 3
Option 2: 2
Option 3: 5
Option 4: 6
Question : A is the centre of a circle whose radius is 8 units, and B is the centre of a circle whose diameter is 8 units. If these two circles touch externally, then the area of the circle with diameter AB is:
Option 1: $36\pi$ sq. units
Option 2: $64\pi$ sq. units
Option 3: $144\pi$ sq. units
Option 4: $256\pi$ sq. units
Question : If for an isosceles triangle, the length of each equal side is $a$ units and that of the third side is $b$ units, then its area will be:
Option 1: $\frac{1}{4}\sqrt{4b^{2}-a^{2}}$ sq. units
Option 2: $\frac{a}{2}\sqrt{2a^{2}-b^{2}}$ sq. units
Option 3: $\frac{b}{4}\sqrt{4a^{2}-b^{2}}$ sq. units
Option 4: $\frac{b}{2}\sqrt{a^{2}-2b^{2}}$ sq. units
Question : The perimeter of a rhombus is $2p$ units, and the sum of the lengths of the diagonals is $m$ units. The area of the rhombus is:
Option 1: $\frac{m^{2}p}{4}$ sq. units
Option 2: $\frac{mp^{2}}{4}$ sq. units
Option 3: $\frac{m^{2} - p^{2}}{4}$ sq. units
Option 4: $\frac{p^{2} – m^{2}}{4}$ sq. units
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