Question : The base of a pyramid is an equilateral triangle of side 10 m. If the height of the pyramid is $40 \sqrt{3}$ m, then the volume of the pyramid is:
Option 1: 1,000 m3
Option 2: 1,200 m3
Option 3: 9,00 m3
Option 4: 8,00 m3
Latest: SSC CGL 2024 final Result Out | SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL Tier 1 Scorecard 2024 Released | SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: 1,000 m3
Solution : Given: The base of a pyramid is an equilateral triangle of side 10 m. The height of the pyramid is $40 \sqrt{3}$ m. Use the formulas, The volume of the pyramid = $\frac{1}{3}\times (\text{The area of the base})\times (\text{Height})$, The area of the equilateral triangle = $\frac{\sqrt{3}}{4}\times (\text{side})^2$ The area of the equilateral triangle = $\frac{\sqrt{3}}{4}\times {10}^2=25\sqrt3$ m2 The volume of the pyramid = $\frac{1}{3}\times 25\sqrt3 \times 40\sqrt3=1000$ m3 Hence, the correct answer is 1,000 m3.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : The base of a right pyramid is an equilateral triangle with a side of 8 cm, and its height is $30 \sqrt{3}$ cm. The volume (in cm$^3$ ) of the pyramid is:
Option 1: $240 \sqrt{3}$
Option 2: $360 \sqrt{3}$
Option 3: $480$
Option 4: $360$
Question : The base of a right prism is an equilateral triangle whose side is 10 cm. If the height of this prism is $10 \sqrt{3}$ cm, then what is the total surface area of the prism?
Option 1: $125 \sqrt{3}$ cm2
Option 2: $325 \sqrt{3}$ cm2
Option 3: $150 \sqrt{3}$ cm2
Option 4: $350 \sqrt{3}$ cm2
Question : The base of a right pyramid is an equilateral triangle, each side of which is 20 cm. Each slant edge is 30 cm. The vertical height (in cm) of the pyramid is:
Option 1: $10 \sqrt{\frac{23}{3}}$
Option 2: $5 \sqrt{3}$
Option 3: $10 \sqrt{3}$
Option 4: $5 \sqrt{\frac{23}{3}}$
Question : A pyramid has an equilateral triangle as its base, of which each side is 8 cm. Its slant edge is 24 cm. The whole surface area of the pyramid (in cm2) is:
Option 1: $(16 \sqrt{3}+24 \sqrt{35})$
Option 2: $(12 \sqrt{3}+24 \sqrt{35})$
Option 3: $(24\sqrt{3}+36\sqrt{35})$
Option 4: $(16\sqrt{3}+48\sqrt{35})$
Question : The height of an equilateral triangle is $7 \sqrt{3}$ cm. What is the area of this equilateral triangle?
Option 1: $36 \sqrt{3}$ cm2
Option 2: $25 \sqrt{3}$ cm2
Option 3: $49 \sqrt{3}$ cm2
Option 4: $32 \sqrt{3}$ cm2
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile