Question : The base of a right pyramid is a square of side $8 \sqrt{2}$ cm and each of its slant edges is of length 10 cm. What is the volume (in cm$^3$) of the pyramid?
Option 1: $256$
Option 2: $224$
Option 3: $426 \frac{2}{3}$
Option 4: $96 \sqrt{2}$
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Correct Answer: $256$
Solution : Given: The base of a right pyramid is a square of side = $8\sqrt{2}$ cm and slant edge = 10 cm. DP = Half of the diagonal of the square ⇒ DP = $\frac{1}{2} \times [\sqrt 2\times 8\sqrt 2] = 8$ cm Now, In a right-angled triangle OPD $OP^2= OD^2- DP^2$ [since $\angle OPD = 90^\circ$] ⇒ $OP^2= 10^2- 8^2= 6^2$ ⇒ $OP = 6$ So, the height of the pyramid = 6 cm Area of square base = $a^2=(8\sqrt 2)^2=128$ cm Now, the volume of the pyramid = $\frac{1}{3} \times \text{area of base}\times 6$ = $\frac{1}{3} \times 128\times 6$ = $256$ cm$^3$ Hence, the correct answer is $256$.
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Question : The base of a right pyramid is an equilateral triangle, each side of which is 20 cm. Each slant edge is 30 cm. The vertical height (in cm) of the pyramid is:
Option 1: $10 \sqrt{\frac{23}{3}}$
Option 2: $5 \sqrt{3}$
Option 3: $10 \sqrt{3}$
Option 4: $5 \sqrt{\frac{23}{3}}$
Question : The base of a right pyramid is an equilateral triangle with a side of 8 cm, and its height is $30 \sqrt{3}$ cm. The volume (in cm$^3$ ) of the pyramid is:
Option 1: $240 \sqrt{3}$
Option 2: $360 \sqrt{3}$
Option 3: $480$
Option 4: $360$
Question : A pyramid has an equilateral triangle as its base, of which each side is 8 cm. Its slant edge is 24 cm. The whole surface area of the pyramid (in cm2) is:
Option 1: $(16 \sqrt{3}+24 \sqrt{35})$
Option 2: $(12 \sqrt{3}+24 \sqrt{35})$
Option 3: $(24\sqrt{3}+36\sqrt{35})$
Option 4: $(16\sqrt{3}+48\sqrt{35})$
Question : In a circle of radius 3 cm, two chords of length 2 cm and 3 cm lie on the same side of a diameter. What is the perpendicular distance between the two chords?
Option 1: $\frac{4 \sqrt{3}-3 \sqrt{2}}{2}$ cm
Option 2: $\frac{4 \sqrt{2}-3 \sqrt{3}}{2}$ cm
Option 3: $\frac{4 \sqrt{2}-3 \sqrt{3}}{3}$ cm
Option 4: $\frac{4 \sqrt{2}-3 \sqrt{3}}{4}$ cm
Question : The length of each side of a triangle is 12 cm. What is the length of the circumradius of the triangle?
Option 1: $8 \sqrt{3} \mathrm{~cm}$
Option 2: $2 \sqrt{3} \mathrm{~cm}$
Option 3: $6 \sqrt{3} \mathrm{~cm}$
Option 4: $4 \sqrt{3} \mathrm{~cm}$
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