Question : The chords PQ and RS of a circle, when produced, meet at a point O. If PQ = 6 cm, OQ = 8 cm, and OS = 7 cm, then the length (in cm) of the chord RS is:
Option 1: 10
Option 2: 12
Option 3: 16
Option 4: 9
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Correct Answer: 9
Solution :
We know that the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord. ⇒ OP × OQ = OR × OS Given that PQ = 6 cm, OQ = 8 cm, and OS = 7 cm. On substituting the values, ⇒ (6 + 8) × 8 = OR × 7 ⇒ 2 × 8 = OR ⇒ OR = 16 cm ⇒ RS = OR – OS = 16 – 7 = 9 cm Hence, the correct answer is 9.
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Question : Two concentric circles are of radii 10 cm and 6 cm. Find the length of the chord of the larger circle which touches the smaller circle.
Option 1: 8 cm
Option 2: 16 cm
Option 3: 12 cm
Option 4: 9 cm
Question : The radius of a circle is 6 cm. The distance of a point lying outside the circle from the centre is 10 cm. The length of the tangent drawn from the outside point to the circle is:
Option 1: 5 cm
Option 2: 6 cm
Option 3: 7 cm
Option 4: 8 cm
Question : The radius of a circle is 5 cm. The length of chord AB in this circle is 6 cm. What is the distance of this chord from the centre of the circle?
Option 1: 4 cm
Option 2: 5 cm
Option 3: 6 cm
Question : In a circle, a diameter AB and a chord PQ (which is not a diameter) intersect each other at X perpendicularly. If AX : BX = 3 : 2 and the radius of the circle is 5 cm, then the length of the chord PQ is:
Option 1: $2\sqrt{13}\;\mathrm{cm}$
Option 2: $5\sqrt{3}\;\mathrm{cm}$
Option 3: $4\sqrt{6}\;\mathrm{cm}$
Option 4: $6\sqrt{5}\;\mathrm{cm}$
Question : O is the centre of this circle. Tangent drawn from a point P, touches the circle at Q. If PQ = 24 cm and OQ = 10 cm, then what is the value of OP?
Option 1: 26 cm
Option 2: 52 cm
Option 3: 13 cm
Option 4: 15 cm
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