1181 Views

the diffusion coffficientof an ideal gas is proportional to its mean free path and mean speed the absolute temperature of an ideal gas increased 4 times and its pressure is increased 2 times as a result the diffusion cofficient of a gas increased x times the value of x is?


oy64147 12th Jun, 2020
Answer (1)
Mounika Sonti 12th Jun, 2020

Hello!!!

Hope you are doing great!!!

Diffusion Coefficient ∝ λx u avg

λ =1/√ 2π  σ ^2 .N

D.C  ∝ u avg /√ 2π  σ ^2 .N

No = P/KT

u avg ∝ √T

D.C ∝ T^3/2 / P

D.C2/D.C1 = 4*√4 /2

= 8/2

=4

Hope it helps!!!

Related Questions

Amrita University B.Tech 2026
Apply
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships
UPES B.Tech Admissions 2026
Apply
Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
UPES Integrated LLB Admission...
Apply
Ranked #18 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS Rankings | 16 LPA Highest CTC
Great Lakes Institute of Mana...
Apply
Admissions Open | Globally Recognized by AACSB (US) & AMBA (UK) | 17.8 LPA Avg. CTC for PGPM 2025
Jain University, Bangalore - ...
Apply
NAAC A++ Approved | Curriculum Aligned with BCI & UGC
Nirma University Law Admissio...
Apply
Grade 'A+' accredited by NAAC | Ranked 33rd by NIRF 2025
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books