Question : The equation of the line if its slope is $-\frac{3}{7}$ and it passes through the point (5, 2) is:
Option 1: $3x+7y=29$
Option 2: $3x-7y=1$
Option 3: $3x+7y=1$
Option 4: $3x-7y=29$
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Correct Answer: $3x+7y=29$
Solution : To find: Equation of the line with slope $-\frac{3}{7}$that passes through the point (5, 2). The equation of a line passing through $(x, y)$ is $y=mx+c$, where $m$ is the slope and $c$ is the y-intercept. Here, $m=-\frac{3}{7}$ and $(x, y)=(5,2)$ $⇒ 2=-\frac{3}{7}×5+c$ $⇒ c=\frac{15}{7}+2$ $⇒ c=\frac{29}{7}$ By putting these values in the equation of the line, $y=mx+c$ $⇒ y=-\frac{3}{7}×x+\frac{29}{7}$ $⇒ 3x+7y=29$ Hence, the correct answer is $3x+7y=29$.
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Question : The graphs of the equations $4 x+\frac{1}{3} y=\frac{8}{3}$ and $\frac{1}{2} x+\frac{3}{4} y+\frac{5}{2}=0$ intersect at a point P. The point P also lies on the graph of the equation:
Option 1: $x + 2y - 5 = 0$
Option 2: $3x - y - 7 = 0$
Option 3: $x - 3y - 12= 0$
Option 4: $4x - y + 7= 0$
Question : The slope of the line passing through the point (7, –2) and ($x$, 1) is $-\frac{3}{10}$. Find $x$.
Option 1: 4
Option 2: 2
Option 3: –4
Option 4: –3
Question : If $2x+\frac{1}{3x}$ = 5, then the value of $\frac{5x}{6x^{2}+20x+1}$ is:
Option 1: $\frac{1}{4}$
Option 2: $\frac{1}{6}$
Option 3: $\frac{1}{5}$
Option 4: $\frac{1}{7}$
Question : What is the slope of the line parallel to the line passing through the points (5, – 1) and (4, – 4)?
Option 1: $– 3$
Option 2: $\frac{–1}{3}$
Option 3: $3$
Option 4: $\frac{1}{3}$
Question : The value of $1 \frac{3}{4}+1 \frac{5}{7} \div 2 \frac{3}{7} \times 2 \frac{3}{7}=$?
Option 1: $1 \frac{11}{28}$
Option 2: $2 \frac{13}{28}$
Option 3: $3 \frac{13}{28}$
Option 4: $4 \frac{23}{28}$
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