Question : The greatest possible length that can be used to measure exactly the lengths of 3 m 15 cm, 5 m, and 6 m 85 cm is:
Option 1: 9 cm
Option 2: 11 cm
Option 3: 7 cm
Option 4: 5 cm
Correct Answer: 5 cm
Solution : Given: The lengths are 3 m 15 cm, 5 m, and 6 m 85 cm. 1 m = 100 cm 3 m 15 cm = 300 + 15 = 315 cm, 6 m 85 cm = 600 + 85 = 685 cm The greatest possible length that can be used to measure exactly the lengths of 315 cm and 685 cm = HCF of 315 and 685 = 5 cm Hence, the correct answer is 5 cm.
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Question : The greatest fraction among $\frac{2}{3}, \frac{5}{6}, \frac{11}{15} \text{ and } \frac{7}{8} \text{ is:}$
Option 1: $\frac{7}{8}$
Option 2: $\frac{11}{15}$
Option 3: $\frac{5}{6}$
Option 4: $\frac{2}{3}$
Question : In ΔABC with sides 8 cm, 9 cm and 12 cm, the angle bisector of the largest angle divides the opposite sides into two segments. What is the length of the shorter segment?
Option 1: $5 \frac{11}{17} {~cm}$
Option 2: $4\frac{11}{17} {~cm}$
Option 3: $6\frac{13}{17} {~cm}$
Option 4: $3\frac{9}{17} {~cm}$
Question : The sides of a triangular field are 62 m, 186 m, and 279 m. Find the greatest length of tape that would be able to exactly measure each of them without any fractions.
Option 1: 62 m
Option 2: 93 m
Option 3: 31 m
Option 4: 30 m
Question : Find the greatest number that exactly divides 15, 30, and 40.
Option 1: 3
Option 2: 40
Option 3: 5
Option 4: 15
Question : Arrange the given ratios in descending order 15 : 7, 5 : 11, and 21 : 77.
Option 1: 21 : 77 > 5 : 11 > 15 : 7
Option 2: 15 : 7 > 5 : 11 > 21 : 77
Option 3: 15 : 7 > 21 : 77 > 5 : 11
Option 4: 5 : 11 > 15 : 7 > 21 : 77
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