63 Views

the heat generated in 5ohm resistorbdue to current flowing through ot is 10cal


poojitha nidubrolu 13th Oct, 2019
Answer (1)
ADITYA KUMAR Student Expert 13th Oct, 2019
Hello there!

Greetings!

Though you haven't completed your question, I got your doubt and is providing you the solution.

We know that , H = I^2Rt

Here R is resistance, I is current, H is the heat and t is time.

Given data:

R1 = 5ohm

H = 10 calories

R2 = 4ohm

Time, t = 1 second

For resistance R1, H= I^2RT

10 = I2 X 5 ohm x1s

I2= 2

Now for resistance R2:

H = I^2Rt

H = 2 X 4 X 1

H=8 calorie

Thankyou

Related Questions

Amity University-Noida B.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Amrita University B.Tech 2026
Apply
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships
UPES B.Tech Admissions 2026
Apply
Last Date to Apply: 28th Feb | Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
Amity University-Noida BBA Ad...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
BML Munjal University | B.Tec...
Apply
A Hero Group Initiative | Up to 100% Scholarships | Highest CTC 32.99 LPA | Average CTC 8.45 LPA | Accepts JEE Score | Applications Closing Soon!
Amity University-Noida MBA Ad...
Apply
Ranked among top 10 B-Schools in India by multiple publications | Top Recruiters-Google, MicKinsey, Amazon, BCG & many more.
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books