Question : The length of a side of an equilateral triangle is 8 cm. The area of the region lying between the circumcircle and the incircle of the triangle is __________ ( Use: $\pi = \frac{22}{7}$)
Option 1: $50\frac{1}{7}\ \text{cm}^2$
Option 2: $50\frac{2}{7}\ \text{cm}^2$
Option 3: $75\frac{1}{7}\ \text{cm}^2$
Option 4: $75\frac{2}{7}\ \text{cm}^2$
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Correct Answer: $50\frac{2}{7}\ \text{cm}^2$
Solution : Given: Side of the equilateral triangle, $a$ = 8 cm Radius of incircle = $\frac{a}{2\sqrt{3}}$ cm Radius of circumcircle = $\frac{a}{\sqrt{3}}$ cm So, the required area = Area of circumcircle – Area of incircle = $\pi (\frac{a}{\sqrt{3}})^2-\pi (\frac{a}{2\sqrt{3}})^2$ = $\pi (\frac{8}{\sqrt{3}})^2-\pi (\frac{8}{2\sqrt{3}})^2$ = $64\pi(\frac{1}{3}-\frac{1}{12})$ = $64×\frac{22}{7}×\frac{1}{4}$ = $\frac{352}{7}$ = $50\frac{2}{7}\ \text{cm}^2$ Hence, the required area is $50\frac{2}{7}\ \text{cm}^2$.
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Question : The circumference of a circle is equal to the perimeter of an equilateral triangle. If the radius of the circle is 7 cm, what is the length of the side of the equilateral triangle?
Option 1: $\frac{22}{3}$ cm
Option 2: $\frac{44}{3}$ cm
Option 3: $44$ cm
Option 4: $22$ cm
Question : The length of the median of an equilateral triangle is $12\sqrt3 \text{ cm}$. Then, the area of the triangle is:
Option 1: $144\text{ cm}^2$
Option 2: $288\sqrt3\text{ cm}^2$
Option 3: $144\sqrt3\text{ cm}^2$
Option 4: $288\text{ cm}^2$
Question : What is the altitude of an equilateral triangle whose side is 15 cm?
Option 1: $15\sqrt3\text{ cm}$
Option 2: $10\sqrt 3\text{ cm}$
Option 3: $\frac{9\sqrt 3 }{2}\text{ cm}$
Option 4: $\frac{15\sqrt 3}{2}\text{ cm}$
Question : In a right-angled triangle $\Delta PQR, PR$ is the hypotenuse of length 20 cm, $\angle PRQ = 30^{\circ}$, the area of the triangle is:
Option 1: $50\sqrt{3}\text{ cm}^{2}$
Option 2: $100\sqrt{3}\text{ cm}^{2}$
Option 3: $25\sqrt{3}\text{ cm}^{2}$
Option 4: $\frac{100}{\sqrt{3}}\text{ cm}^{2}$
Question : If the diameter of a sphere is 7 cm, find the volume of the sphere. (use $\pi=\frac{22}{7}$) (Rounded up to two decimal places).
Option 1: $184 \ \text{cm}^3$
Option 2: $201.34\ \text{cm}^3$
Option 3: $128.87 \ \text{cm}^3$
Option 4: $179.67 \ \text{cm}^3$
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