Question : The lengths of the diagonals of a rhombus are 24 cm and 10 cm, then the perimeter of the rhombus (in cm) is:
Option 1: 52
Option 2: 56
Option 3: 68
Option 4: 72
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Correct Answer: 52
Solution : Given: The lengths of the diagonals of a rhombus are 24 cm and 10 cm. So, the length of the sides = $\sqrt{(\frac{24}{2})^2+(\frac{10}{2})^2}$ = $\sqrt{12^2+5^2}$ = $\sqrt{169}$ = $13$ $\therefore$ The perimeter of the rhombus = (4 × 13) = 52 cm Hence, the correct answer is 52.
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Question : The diagonals of a rhombus are 12 cm and 16 cm, respectively. The length of one side is:
Option 1: 8 cm
Option 2: 6 cm
Option 3: 10 cm
Option 4: 12 cm
Question : The perimeter of a Rhombus is 60 cm and one of its diagonal is 24 cm. The area of the Rhombus is:
Option 1: 108 sq.cm
Option 2: 216 sq.cm
Option 3: 432 sq.cm
Option 4: 206 sq.cm
Question : If the diagonals of a rhombus are 8 cm and 6 cm, then the square of its side is:
Option 1: $25\;\mathrm{cm^2}$
Option 2: $55\;\mathrm{cm^2}$
Option 3: $64\;\mathrm{cm^2}$
Option 4: $36\;\mathrm{cm^2}$
Question : The lengths of the three medians of a triangle are $9\;\mathrm{cm}$, $12\;\mathrm{cm}$, and $15\;\mathrm{cm}$. The area (in $\mathrm{cm^2}$) of the triangle is:
Option 1: $24$
Option 2: $72$
Option 3: $48$
Option 4: $144$
Question : The area of a rhombus is 256 square cm, and one of its diagonals is twice the other in length. The length of its larger diagonal is:
Option 1: 32 cm
Option 2: 16 cm
Option 3: 48 cm
Option 4: 24 cm
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