Question : The perpendicular drawn from the vertices, to the opposite sides of a triangle, meet at the point whose name is:
Option 1: incentre
Option 2: circumcentre
Option 3: centroid
Option 4: orthocentre
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: orthocentre
Solution : AD is perpendicular to BC. BE is perpendicular to AC. CF is perpendicular to AB. They meet at a point called the orthocentre. Hence, the correct answer is 'orthocentre'.
Candidates can download this e-book to give a boost to thier preparation.
Answer Key | Eligibility | Application | Admit Card | Preparation Tips | Result | Cutoff
Question : The intersection point of the medians of a triangle is called:
Option 1: Orthocentre
Option 2: Incentre
Option 3: Circumcentre
Option 4: Centroid
Question : What are the coordinates of the centroid of a triangle whose vertices are A (2, 5), B (–4, 0), and C (5, 4)?
Option 1: (–1, 3)
Option 2: (1, 3)
Option 3: (1, –3)
Option 4: (–1, –3)
Question : Let $\text{AX}\perp \text{BC}$ of an equilateral triangle $\text{ABC}$. Then the sum of the perpendicular distances of the sides of $\triangle \text{ABC}$ from any point inside the triangle is:
Option 1: Equal to $BC$
Option 2: Equal to $AX$
Option 3: Less than $AX$
Option 4: Greater than $AX$
Question : An equilateral triangle has sides of 18 cm each. The ratio of the inradius to circumradius of the triangle is:
Option 1: 2 : 1
Option 2: 3 : 2
Option 3: 3 : 4
Option 4: 1 : 2
Question : In an equilateral triangle ABC, P is the centroid of this triangle. Side of $\triangle A B C$ is $16 \sqrt{3} \ \text{cm}$. What is the distance of point P from side BC?
Option 1: 8 cm
Option 2: 12 cm
Option 3: 9 cm
Option 4: 10 cm
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile