Question : The population of a certain village increases by 5% annually. Its present population is 8200. After two years the population will be (approximately):
Option 1: 9200
Option 2: 9246
Option 3: 9040
Option 4: 9161
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Correct Answer: 9040
Solution : Present population, $P$ = 8200 Time, $t$ = 2 years Rate, $r$ = 5% Population after $t$ years at the rate of $r$ % = $P(1+\frac{r}{100})^{t}$ = $8200(1+\frac{5}{100})^{2}$ = $8200(\frac{21}{20})^{2}$ = $8200×\frac{441}{400}$ = $9040.5\approx 9040$ Hence, the correct answer is 9040.
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Question : The population of the village was 12,000 two years ago. If it increased by 2.5% and 3%, respectively, in the last two years, then what is the present population of the village?
Option 1: 12,669
Option 2: 12,607
Option 3: 12,652
Option 4: 12,731
Question : The population of a city increases compounded by 10% annually. The present population of this city is 1,33,100. What was the population of the city 2 years ago?
Option 1: 1,01,000
Option 2: 1,10,000
Option 3: 1,21,000
Option 4: 1,00,000
Question : Two years ago, the population of a small town was 60,000. It increased by 5% in the first year, but due to the pandemic, it decreased by 10% in the second year. What is its present population (after the end of 2 years)?
Option 1: 56,700
Option 2: 56,900
Option 3: 3300
Option 4: 55,700
Question : An epidemic broke out in a village where 5% of the population died. Of the remaining population, 20% fled in panic. If the present population is 4655, what was the original population of the village?
Option 1: 6000
Option 2: 6125
Option 3: 5955
Option 4: 5995
Question : Finance Commission is appointed by the President of India after every
Option 1: 5 years
Option 2: 6 years
Option 3: 4 years
Option 4: None of these
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