Question : The population of a town increases at the rate of 20% per annum. If the town's population will be 69,120 after 2 years, then what is the town's present population?
Option 1: 48,000
Option 2: 42,000
Option 3: 40,000
Option 4: 36,000
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Correct Answer: 48,000
Solution : Use the formula: Amount = P[$(1+\frac{r}{100})^n$] where P is principal, $r$ is the rate of interest compounded annually for $n$ years. The population increases at the rate of 20% per annum, ⇒ 69,120 = P[$(1+\frac{20}{100})^2$] ⇒ 69,120 = P$(\frac{6}{5})^2$ ⇒ P = $\frac{69120×25}{36}$ ⇒ P = 48,000 Hence, the correct answer is 48,000.
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Question : If the population of a town is 12,000 and the population increases at the rate of 10% per annum, then find the population after 3 years.
Option 1: 15,972
Option 2: 12,200
Option 3: 11,200
Option 4: 10,200
Question : The population of a village decreases at the rate of 40% per annum. If its population 2 years ago was 15,000, then find the present population.
Option 1: 5400
Option 2: 3500
Option 3: 4450
Option 4: 4400
Question : At what rate of compound interest (compounding annually) per annum will a sum of Rs. 250000 becomes Rs. 275625 in 2 years?
Option 1: 8% per annum
Option 2: 3% per annum
Option 3: 10% per annum
Option 4: 5% per annum
Question : Raja borrowed INR 15,000 on simple interest at the rate of 13% per annum and lent it on compound interest at the rate of 15% per annum, compounded annually. What is Raja's gain in two years?
Option 1: INR 1,080.00
Option 2: INR 1,125.00
Option 3: INR 937.50
Option 4: INR 865.50
Question : At present, the number of trees in a village is 52,020. It increases annually at the rate of 2%. What was the number of trees in the village two years ago?
Option 1: 45,000
Option 2: 51,250
Option 3: 50,000
Option 4: 48,000
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