Question : Mother told her daughter, "Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be". Find the present ages of the mother and the daughter, respectively.

Option 1: 45 and 15

Option 2: 40 and 10

Option 3: 42 and 12

Option 4: 50 and 20

Question : Directions: A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, then what is the present age of the wife?

Option 1: 60 years 

Option 2: 51 years

Option 3: 48 years 

Option 4: 45 years

Question : Direction: Two years ago, Aadhya was three times as old as his son, and two years hence, twice her age will be equal to five times that of her son. Find Aadhya's present age.

Option 1: 38 years

Option 2: 36 years

Option 3: 34 years

Option 4: 42 years

Question : The sum of the ages of the mother and her daughter is 60 years. 12 years ago, the mother was eight times as old as her daughter. How old is the daughter at present?

Option 1: 20 years

Option 2: 28 years

Option 3: 16 years

Option 4: 12 years

Question : Direction: The age of the father 4 years ago was 8 times the age of his son. At present, the father's age is 4 times that of his son. Find the present age of son.

Option 1: 9 years

Option 2: 7 years

Option 3: 14 years

Option 4: 18 years