8 Views

Question : The radius of a sphere is doubled. The percentage increase in its surface area is ______.

Option 1: 75%

Option 2: 100%

Option 3: 300%

Option 4: 400%


Team Careers360 6th Jan, 2024
Answer (1)
Team Careers360 23rd Jan, 2024

Correct Answer: 300%


Solution : Let the radius of the sphere be $r$ units.
So, the surface area of the sphere = $4\pi r^2$ sq. units
After doubling, the new radius = 2$r$ units
So, the new surface area = $4\pi (2r)^2=16\pi r^2$ sq. units
$\therefore$ The percentage increase = $\frac{16\pi r^2-4\pi r^2}{4\pi r^2}×100=\frac{12\pi r^2}{4\pi r^2}×100= 300\%$
Hence, the correct answer is 300%.

Know More About

Related Questions

Amity Online MBA
Apply
Apply for an Online MBA from Amity Online.
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
View All Application Forms

Upcoming Exams

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books