Question : The ratio of the angles of a triangle is 2 : 2 : 5. What is the largest angle?
Option 1: $120^\circ$
Option 2: $80^\circ$
Option 3: $110^\circ$
Option 4: $100^\circ$
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Correct Answer: $100^\circ$
Solution : Let the angles of the triangle be $2x, 2x,$ and $5x$ respectively. We know that the angles of a triangle are $180^\circ$. Therefore, by angle sum property: $2x + 2x + 5x = 180^\circ$ ⇒ $9x = 180^\circ$ $\therefore x = 20^\circ$ So, the largest angle $=5\times20^\circ = 100^\circ$ Hence, the correct answer is $100^\circ$.
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Question : The ratio of the angles of a triangle is 1 : 2 : 6. What is the smallest angle?
Option 1: $40^\circ$
Option 2: $45^\circ$
Option 3: $30^\circ$
Option 4: $20^\circ$
Question : If $ABCD$ is a cyclic quadrilateral with $\angle A=50^{\circ},\angle B=80^{\circ}$, then $\angle C$ and $ \angle D$ are:
Option 1: $100^{\circ}$ and $130^{\circ}$
Option 2: $115^{\circ}$ and $115^{\circ}$
Option 3: $110^{\circ}$ and $120^{\circ}$
Option 4: $130^{\circ}$ and $100^{\circ}$
Question : In a $\triangle$ ABC, BC is extended to D and $\angle$ ACD = $120^{\circ}$. $\angle$ B = $\frac{1}{2}\angle$ A. Then $\angle$ A is:
Option 1: $60^{\circ}$
Option 2: $75^{\circ}$
Option 3: $80^{\circ}$
Option 4: $90^{\circ}$
Question : In $\triangle ABC$, the internal bisectors of $\angle B$ and $\angle C$ meet at point $O$. If $\angle A = 80^\circ$, then $\angle BOC$ is equal to:
Option 1: $100^\circ$
Option 2: $120^\circ$
Option 3: $130^\circ$
Option 4: $140^\circ$
Question : $O$ is the orthocentre of triangle $ABC$, and if $\angle BOC = 110^\circ$, then $\angle BAC$ will be:
Option 1: $110^\circ$
Option 2: $70^\circ$
Option 3: $100^\circ$
Option 4: $90^\circ$
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