Question : The ratio of the speeds of Aman, Kamal, and Manan is $4:5:6$, respectively. What is the ratio of the time taken by Aman, Kamal, and Manan, respectively, to cover the same distance?
Option 1: $10:12:15$
Option 2: $6:5:4$
Option 3: $4:5:6$
Option 4: $15:12:10$
Correct Answer: $15:12:10$
Solution : Required ratio = $(\frac{1}{4}):(\frac{1}{5}):(\frac{1}{6})$ = $(\frac{1}{4}×60):(\frac{1}{5}×60):(\frac{1}{6}×60)$ [Multiplying each fraction by LCM of (4, 5 and 6) i.e., 60] = $15:12:10$ Hence, the correct answer is $15:12:10$.
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Question : The time taken to travel the same distance by three cars is in the ratio of 12:15:10. What is the ratio of the speeds of the three cars?
Option 1: 4 : 5 : 6
Option 2: 4 : 6 : 5
Option 3: 5 : 4 : 6
Option 4: 5 : 6 : 4
Question : Raman, Manan, and Kamal are partners and invest in a business such that Raman invests $\frac{2}{5}$th of the total and Manan invests $\frac{3}{8}$th of the total. What is the ratio of profits of Raman, Manan and Kamal, respectively?
Option 1: 16 : 15 : 9
Option 2: 16 : 15 : 31
Option 3: 2 : 3 : 5
Option 4: 15 : 16 : 9
Question : The speeds of two bodies are in the ratio 2 : 3. If the difference in the time taken to cover 50 m is 10 sec, then find the difference in their speeds.
Option 1: $\frac{8}{9} \mathrm{~m} / \mathrm{sec}$
Option 2: $\frac{5}{6} \mathrm{~m} / \mathrm{sec}$
Option 3: $\frac{6}{5} \mathrm{~m} / \mathrm{sec}$
Option 4: $\frac{7}{5} \mathrm{~m} / \mathrm{sec}$
Question : The speed of a boat in still water is 20 km/hr, while the river is flowing at a speed of 8 km/hr and the time taken to cover a certain distance upstream is 6 hr more than the time taken to cover the same distance downstream. Find the distance.
Option 1: 120 km
Option 2: 336 km
Option 3: 126 km
Option 4: 125 km
Question : The areas of the two triangles are in the ratio 4 : 3 and their heights are in the ratio 6 : 5. Find the ratio of their bases.
Option 1: 5 : 6
Option 2: 10 : 9
Option 3: 6 : 5
Option 4: 9 : 10
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