979 Views

The resultant of two forces P and Q is R. If Q is double the new resultant becomes perpendicular to P. Prove that P =R by triangle law.


Azhar aftab 29th Mar, 2019
Answer (1)
Debosmitha Bhattacharyya Student Expert 29th Mar, 2019

Hello Azhar,

Resultant of two forces P and Q is R


R = P + Q


|R| = sqrt(P^2 + Q^2 + 2PQCosθ)


When Q is doubled new resultant R’ is


R’ = P + 2Q


Since it is perpendicular to P, the dot product of R’ and P is zero


(R’).(P) = 0


(P + 2Q).(P) = 0


P^2 + 2PQCosθ = 0


(Dot product of P and P is P^2 and that of P and 2Q is 2PQCosθ)


Cosθ = -P/(2Q)


R = sqrt(P^2 + Q^2 + 2PQCosθ)


R = sqrt(P^2 + Q^2 + 2PQ*(-P/(2Q))


R = sqrt(P^2 + Q^2 - P^2)


R = Q

Hope this helps.

Related Questions

Amity University-Noida Law Ad...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Amity University-Noida LLM Ad...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Chandigarh University Admissi...
Apply
NAAC A+ Accredited | Among top 2% Universities Globally (QS World University Rankings 2026)
Geeta Institute of Law-Admiss...
Apply
In-house judicial coaching | Proven success in National Moot Court Competitions
GNIOT BA LLB Admissions 2026
Apply
NAAC A+ Accredited | Students | Moot Court Session | Legal Aid Clinics | | Scholarships to Meritorious
Manav Rachna University Law A...
Apply
Admissions open for B.A. LL.B. (Hons.), B.B.A. LL.B. (Hons.) and LL.B Program (3 Years) | School of Law, MRU ranked No. 1 in Law Schools of Excelle...
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books