Question : The sides of a triangle are 16 cm, 12 cm, and 20 cm. Find the area.
Option 1: 64 cm2
Option 2: 112 cm2
Option 3: 96 cm2
Option 4: 81 cm2
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Correct Answer: 96 cm2
Solution : The given triangle with sides 16 cm, 12 cm, and 20 cm is a right-angled triangle. (since $20^2 = 16^2 + 12^2$) The area of a right-angled triangle, $\text{Area} =\frac{1}{2} \times \text{base} \times \text{height}$ ⇒ $\text{Area} = \frac{1}{2} \times 16 \times 12 = \operatorname{ 96 cm^2 }$ Hence, the correct answer is 96 cm2.
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Question : The sides of a triangle are 20 cm, 21 cm, and 29 cm. The area of the triangle formed by joining the midpoints of the sides of the triangle will be:
Option 1: $67 \frac{2}{3}$ cm2
Option 2: $52 \frac{1}{2}$ cm2
Option 3: $47 \frac{1}{2}$ cm2
Option 4: $58 \frac{1}{3}$ cm2
Question : The sides of a triangle are of length 8 cm, 15 cm, and 17 cm. Find the area of the triangle.
Option 1: 65 cm2
Option 2: 75 cm2
Option 3: 60 cm2
Option 4: 70 cm2
Question : In an isosceles triangle, if the unequal side is 8 cm and the equal sides are 5 cm, then the area of the triangle is:
Option 1: 12 cm2
Option 2: 25 cm2
Option 3: 6 cm2
Option 4: 11 cm2
Question : If the total surface area of a cube is 96 cm2, its volume is:
Option 1: 56 cm3
Option 2: 16 cm3
Option 3: 64 cm3
Option 4: 36 cm3
Question : If the altitude of a triangle is 8 cm and its corresponding base is 12 cm, then the area of the triangle will be:
Option 1: 96 cm2
Option 2: 48 cm2
Option 3: 84 cm2
Option 4: 24 cm2
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