Question : The sides of a triangle are in the ratio $\frac{1}{3}: \frac{1}{5}: \frac{1}{6}$. If the perimeter is 147 cm, then the length of the smallest side is_____.
Option 1: 12 cm
Option 2: 25 cm
Option 3: 30 cm
Option 4: 35 cm
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Correct Answer: 35 cm
Solution : Given that the sides of a triangle are in the ratio $\frac{1}{3}: \frac{1}{5}: \frac{1}{6}$ And Perimeter = 147 cm Let the sides be $\frac{x}{3},$ $\frac{x}{5},$ and $\frac{x}{6}$ According to the question, $\frac{x}{3}+\frac{x}{5}+\frac{x}{6}=147$ ⇒ $\frac{10x+6x+5x}{30}=147$ ⇒ $21x=147\times 30$ ⇒ $x=7\times 30 $ ⇒ $x=210$ cm ⇒ Smallest side = $\frac{x}{6}=\frac{210}{6}=35$ cm Hence, the correct answer is 35 cm.
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Question : If the measures of the angles of a triangle are in the ratio 1 : 2 : 3, and if the length of the smallest side of the triangle is 10 cm, then the length of the longest side is:
Option 1: 20 cm
Question : $\triangle ABC \sim \triangle DEF$ such that AB = 9.1 cm and DE = 6.5 cm. If the perimeter of $\triangle DEF = 25$ cm, then the perimeter of $\triangle ABC$ is:
Option 1: 40 cm
Option 2: 30 cm
Option 3: 35 cm
Option 4: 45 cm
Question : The ratio of the length of each equal side and the third side of an isosceles triangle is 3 : 5. If the area of the triangle is $30 \sqrt{11}$ cm2, then the length of the third side (in cm) is:
Option 1: $10\sqrt{6}$
Option 2: $5\sqrt{6}$
Option 3: $13\sqrt{6}$
Option 4: $11\sqrt{6}$
Question : The sides of a triangle are in the ratio $\frac{1}{2}:\frac{1}{3}:\frac{1}{4}$ and its perimeter is 104 cm. The length of the longest side (in cm) is:
Option 1: 52
Option 2: 48
Option 3: 32
Option 4: 26
Question : $\triangle PQR$ is right-angled at $Q$. The length of $PQ$ is 5 cm and $\angle P R Q=30^{\circ}$. Determine the length of the side $QR$.
Option 1: $5 \sqrt{3}~cm$
Option 2: $3 \sqrt{3}~cm$
Option 3: $\frac{1}{\sqrt{3}}~cm$
Option 4: $\frac{5}{\sqrt{3}}~cm$
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