Question : The sides of the three cubes of metal are $15 \text{ cm}, 18 \text{ cm}$ and $25 \text{ cm}$, respectively. Find the side (in $\text{cm}$) of the new cube formed by melting these cubes together.
Option 1: $9 \sqrt[3]{388}$
Option 2: $6 \sqrt[3]{388}$
Option 3: $7 \sqrt[3]{388}$
Option 4: $4 \sqrt[3]{388}$
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $4 \sqrt[3]{388}$
Solution : Let the side of the new cube be $a\text{ cm}$. Volume of 1st cube, $V{_1} = 15^3 = 3375\text{ cm}^3$ Volume of 2nd cube, $V{_2} = 18^3 =5832 \text{ cm}^3$ Volume of 3rd cube, $V{_3} = 25^3 = 15625\text{ cm}^3$ $\therefore$ Volume of new cube, $a^3= V{_1}+V{_2}+V{_3}$ $⇒a^3 = 3375+5832+15625 = 24832\text{ cm}^3$ $\therefore a = \sqrt[3]{24832} =4\sqrt[3]{388}\text{ cm}$ Hence, the correct answer is $4\sqrt[3]{388}$.
Candidates can download this e-book to give a boost to thier preparation.
Application | Eligibility | Admit Card | Answer Key | Preparation Tips | Result | Cutoff
Question : PQRS is a square with a side of 10 cm. A, B, C, and D are mid-points of PQ, QR, RS, and SP, respectively. Then, the perimeter of the square ABCD so formed is:
Option 1: $10\sqrt{2}\ \text{cm}$
Option 2: $20\sqrt{2}\ \text{cm}$
Option 3: $25\sqrt{2}\ \text{cm}$
Option 4: $15\sqrt{2}\ \text{cm}$
Question : The length of the diagonals of a rhombus is 40 cm and 60 cm. What is the length of the side of the rhombus?
Option 1: $50 \sqrt{3} \ \text{cm}$
Option 2: $20 \sqrt{3}\ \text{cm}$
Option 3: $10 \sqrt{13}\ \text{cm}$
Option 4: $40 \sqrt{13}\ \text{cm}$
Question : The three sides of a triangle are 7 cm, 9 cm, and 8 cm. What is the area of the triangle?
Option 1: $12 \sqrt{3} \;\mathrm{Sq} . \mathrm{cm}$
Option 2: $10\sqrt{3} \;\mathrm{Sq} . \mathrm{cm}$
Option 3: $12 \sqrt{5} \;\mathrm{Sq} . \mathrm{cm}$
Option 4: $2 \sqrt{5} \;\mathrm{Sq} . \mathrm{cm}$
Question : The sides of a triangle are 9 cm, 6 cm, and 5 cm. What is the value of the circumradius of this triangle?
Option 1: $\frac{9 \sqrt{2}}{2} \mathrm{~cm}$
Option 2: $\frac{9 \sqrt{3}}{5} \mathrm{~cm}$
Option 3: $\frac{9 \sqrt{3}}{4} \mathrm{~cm}$
Option 4: $\frac{27 \sqrt{2}}{8} \mathrm{~cm}$
Question : The distance between the centres of two circles with radii of 9 cm and 16 cm is 25 cm. The length of the segment of the tangent between them is:
Option 1: $24\ \text{cm}$
Option 2: $25\ \text{cm}$
Option 3: $\frac{50}{3}\ \text{cm}$
Option 4: $12\ \text{cm}$
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile