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the strengthog magnetic field is increased by 21% the frequency of magnetic needle


Sham Sudar 12th Aug, 2019
Answer (1)
NAVEEN MEENA Student Expert 12th Aug, 2019

Dear student, first of all we will find the time period and 1/T is frequency.

So, we know that the time period of any oscillating thing is given by

T = 2 × pi × sqrt( I/M*B)

Now, frequency, f =1/T

=>(1/2*pi)×sqrt( M*B/I)

Now in the above equation 2*pi, I amd M are constant. Therefore,

f is directly proportional to B.

Now applying the formula -

((f2/f1) - 1)×100 =((B2/B1) - 1)×100

In the question its given that the increase is by 21% so putting this value on the right hand side

((f2/f1) - 1)×100 =10%

So the frequency of magnetic needle will be 10%.

All the best 

Hope this helps 

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