Question : The table given below shows the expenditure of two companies in different years.
$J_1$ = The total expenditure of Company L in all 5 years. $J_2$ = The total expenditure of company M in all 5 years. What is the value of ($J_1:J_2$)?
Option 1: 27 : 23
Option 2: 21 : 29
Option 3: 23 : 27
Option 4: 29 : 23
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Correct Answer: 23 : 27
Solution : $J_1$ = The total expenditure of Company L in all 5 years = 200 + 150 + 300 + 100 + 400 = 1150 $J_2$ = The total expenditure of company M in all 5 years = 500 + 350 + 250 + 150 + 100 = 1350 $\therefore J_1:J_2$ = 1150 : 1350 = 23 : 27 Hence, the correct answer is 23 : 27.
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Question : The table given below shows the sales of bikes and cars of five companies.
$J_1$ = The average sale of bikes of companies P, Q, and R. $J_2$ = The average sale of cars of companies R, S, and T. What is the value of ($J_1:J_2$)?
Option 1: 24 : 11
Option 2: 8 : 25
Option 3: 7 : 24
Option 4: 25 : 8
Question : The table given below shows the number of salesmen in five companies.
The number of salesmen in J is what percentage of the number of salesmen in K?
Option 1: 250%
Option 2: 150%
Option 3: 125%
Option 4: 225%
Question : The table given below shows the sales turnover of 5 different companies.
The sales turnover of company A is what percentage of the sales turnover of company C?
Option 1: 60%
Option 2: 50%
Option 3: 40%
Option 4: 75%
Question : The table given below shows the number of trucks sold by six companies.
Number of trucks sold by L is what per cent of the number of trucks sold by J?
Option 1: 100 percent
Option 2: 250 percent
Option 3: 200 percent
Option 4: 150 percent
Question : Directions: Select the missing number from the given responses.
Option 1: 46
Option 2: 69
Option 3: 29
Option 4: 78
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