Question : The three sides of a triangle are 7 cm, 9 cm, and 8 cm. What is the area of the triangle?
Option 1: $12 \sqrt{3} \;\mathrm{Sq} . \mathrm{cm}$
Option 2: $10\sqrt{3} \;\mathrm{Sq} . \mathrm{cm}$
Option 3: $12 \sqrt{5} \;\mathrm{Sq} . \mathrm{cm}$
Option 4: $2 \sqrt{5} \;\mathrm{Sq} . \mathrm{cm}$
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Correct Answer: $12 \sqrt{5} \;\mathrm{Sq} . \mathrm{cm}$
Solution : Using the formula: $s = \frac{(a + b + c)}{2}$ $s = \frac{(7 + 9 + 8)}{2}$ $s = \frac{24}{2}$ $s = 12$ cm Now, plug the values of a, b, c, and s into Heron's formula to find the area of the triangle: $\sqrt{(s(s - a)(s - b)(s - c))}$ $=\sqrt{(12(12 - 7)(12 - 9)(12 - 8))}$ $=\sqrt{(12 × 5 × 3 × 4)}$ $=12\sqrt{5}$ Sq. cm Therefore, the area of the triangle with side lengths 7 cm, 9 cm, and 8 cm is approximately $12\sqrt{5}$ Sq. cm Hence, the correct answer is $12 \sqrt{5} \;\mathrm{Sq}. \mathrm{cm}$.
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Question : The sides of a triangle are 9 cm, 6 cm, and 5 cm. What is the value of the circumradius of this triangle?
Option 1: $\frac{9 \sqrt{2}}{2} \mathrm{~cm}$
Option 2: $\frac{9 \sqrt{3}}{5} \mathrm{~cm}$
Option 3: $\frac{9 \sqrt{3}}{4} \mathrm{~cm}$
Option 4: $\frac{27 \sqrt{2}}{8} \mathrm{~cm}$
Question : Find the area of an equilateral triangle whose sides are 12 cm.
Option 1: $38 \sqrt{3} \mathrm{~cm}^2$
Option 2: $35 \sqrt{3} \mathrm{~cm}^2$
Option 3: $34 \sqrt{3} \mathrm{~cm}^2$
Option 4: $36 \sqrt{3} \mathrm{~cm}^2$
Question : $\triangle \mathrm {ABC}$ is similar to $\triangle \mathrm{PQR}$ and $\mathrm{PQ}=10 \mathrm{~cm}$. If the area of $\triangle \mathrm{ABC}$ is $32 \mathrm{~cm}^2$ and the area of $\triangle \mathrm{PQR}$ is $50 \mathrm{~cm}^2$, then the length of $A B$ (in $\mathrm{cm}$ ) is equal to:
Option 1: 10
Option 2: 4
Option 3: 6
Option 4: 8
Question : In an equilateral triangle, the circumradius is 14 cm. What is the length of the median in this triangle?
Option 1: $14 \sqrt{3} \mathrm{~cm}$
Option 2: $21 \mathrm{~cm}$
Option 3: $18 \sqrt{3} \mathrm{~cm}$
Option 4: $7 \sqrt{3} \mathrm{~cm}$
Question : In an equilateral triangle STU, inradius is $5 \sqrt{3 }\mathrm{~cm}$. What is the length of the side of this equilateral triangle?
Option 1: $20 \sqrt{3} \mathrm{~cm}$
Option 2: $18 \sqrt{3} \mathrm{~cm}$
Option 3: $30 \mathrm{~cm}$
Option 4: $24 \mathrm{~cm}$
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