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the time period of a satellite of earth is 5h if the separation between the Earth and the satellite is increased to 4 times the previous value the new time period will become ?


siddhantyadavsonuom 3rd Jul, 2020
Answer (1)
Mounika Sonti 3rd Jul, 2020

Hello!!!

Hope you are doing great!!!

From Kepler's Third law,

T^2 is directly proportional to R^3

=(T1/T2)^2 = (R1/R2)^3

=(T1/T2)= (R1/R2)^3/2 = (1/4)^3/2

=T2/T1 = (4)^3/2

=8

=T2 = 8*T1

=8*5

=40hrs

Hope it helps!!

1 Comment
Comments (1)
3rd Jul, 2020
Thanks
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