N2O4 ---------NO2.        Initially N2O4 has conc.= 1            then at equilibrium N2O4 has conc.1-X. And NO2 has conc. =2x         initially we have taken N2O4 =1 Molar mass =92 .V.D at eq.=30 .M.w.=60.

n initial/ n final =M final/M initial

1/1-X+2X=60/92

1/1+X=60/92

1+X=92/60

X=92/60 -1

X=32/60

X=0.53           percentage dissociation=0.53 X 100=53

Solving related questions ask on Byjus, Meritnation etc. It's not a educational site, it's carrer counselling site

Only Career related questions should be asked..,

Joint Entrance Examination (Main)

Application | Preparation Tips | Question Paper | Admit Card | Eligibility | Answer Key | Counselling | College Predictor | Rank Predictor | Accepting Colleges

Get Updates Brochure