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the wavelength of the first line in balmer series the hydrogen spectrum is lambda what is the wavelength of second line


KULDEEP SALUNKE 25th Apr, 2020
Answer (1)
Mounika Sonti 20th May, 2020

Hello!!!!

Hope you are doing great!!!!

According to rydberg's equation 1/λ = RZ 2 (1/n 1 2 - 1/n 2 2 )

λ is inversly proportional to n 2

therefore ..;;

λ1/λ2=n2 2 /n1 2

As balmer series start from first line i.e, n1=2,n2=3,λ1=λ ,λ2=?

λ/λ2=3^2/2^2

λ/λ2=9/4

Therefore., wave length of second line in balmer series ,, λ2=4λ/9

Hope it helps !!!!!



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