1)_C_C_C_C_

Number of ways in which 3 vowels can be arranged in the 5 places=5P3

Number of ways in which 4 consonants can be arranged in their designated places=4P4

Total ways such that no two vowels are together=5P3*4P4=1440.

2) Take the vowels together and treat them as single entity. No. Of ways to arrange them is 5!.The vowels in themselves can be arranged in 3! Ways. Therefore the total number of ways such that vowels occur together=5! *3!