Dear Ravi,

The solution for this is as follows:-

As, three dice are thrown simultaneously. So , The combinations that result in getting sum of the digits of 15 are:

(5, 5, 5), (3, 6, 6), (4, 5, 6)

Total number of permutations for the above combinations:

1+3!/2! +3! =10

Desirable outcomes=10

Total number of outcomes if 3 dice are thrown: 6 x 6 × 6 = 216.

Therefore, Probability= 10/216= 5/108.

Thus, Answer is 5/108

Hope this sorted your query.

All the Best!!