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two trains each 100m long moving in opposite directions cross each other in 8 seconds. if one is moving twice as fast as the other, then the speed of the faster train is?


niranjan 27th Sep, 2020
Answer (1)
NAVYA BOINPALLY Student Expert 27th Sep, 2020

Hi


Let the speed of the slower train be x m/sec

then, the speed of the faster train = 2x m/sec

Relative speed = (x+2x) m/sec = 3x m/sec

therefore, (100 +100)/8 = 3x

24x=200

x=25/3

so, the speed of the faster train is 50/3 m/sec

(50/3 x 18/5) km/hr

the speed of the faster train is 60 km/hr.


Hope this information is helpful.

1 Comment
Comments (1)
27th Sep, 2020
thank you so much
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