Dear Saiprasad,



Taking m1 and m2 as mass of first and second rod respectively.



m1=4×2= 8kg (m = lamda × lenght)



m2=6×3=18kg



Where lamda is linear density.



Now lets say the interface is our reference which is assumed to be (0,0)



Therefore, the coordinates and Centre of two rods is (-1,0) and (1.5,0) respectively.



Using the formula of Centre of mass -



r = (m1×r1 + m2×r2) /(m1+m2)



=>( 8×(-1) + 18×(1.5))/22



=> 19/22 =0.8636



Hope this helps :)