Question : $A$ varies directly as $(B+18)$ and $A=108$ when $B=36$. Find the value of $A$ when $B=68$.
Option 1: 75
Option 2: 86
Option 3: 127
Option 4: 172
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Correct Answer: 172
Solution : A varies directly as $(B+18)$ So, $\frac{A_1}{A_2} = \frac{B_1+18}{B_2+18}$ ⇒ $\frac{108}{A_2} = \frac{36+18}{68+18}$ ⇒ $\frac{108}{A_2} = \frac{54}{86}$ ⇒ $A_2 = 172$ Hence, the correct answer is 172.
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