Question : What is the difference of the factors of the expression $x^2+\frac{1}{x^2}-6$?
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: 4
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Correct Answer: 4
Solution : $x^2+\frac{1}{x^2}-6$ = $x^2+\frac{1}{x^2}-2-4$ = $x^2+\frac{1}{x^2}-2×x^2×\frac{1}{x^2}-(2)^2$ = $(x-\frac{1}{x}^2)-(2)^2$ = $(x-\frac{1}{x}+2)(x-\frac{1}{x}-2)$ These are the two factors. So, the difference between them is $(x-\frac{1}{x}+2-x+\frac{1}{x}+2)=4$ Hence, the correct answer is 4.
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Question : If $x-\frac{1}{x}=5, x \neq 0$, then what is the value of $\frac{x^6+3 x^3-1}{x^6-8 x^3-1} ?$
Option 1: $\frac{3}{8}$
Option 2: $\frac{13}{12}$
Option 3: $\frac{4}{9}$
Option 4: $\frac{11}{13}$
Question : If $x+\frac{1}{x}=6$, then find the value of $\frac{3 x}{2 x^2-5 x+2}$.
Option 1: $1$
Option 2: $\frac{3}{7}$
Option 3: $\frac{2}{3}$
Option 4: $0$
Question : If $x-\frac{3}{x}=6, x \neq 0$, then the value of $\frac{x^4-\frac{27}{x^2}}{x^2-3 x-3}$ is:
Option 1: 80
Option 2: 270
Option 3: 54
Option 4: 90
Question : If $x^{4}+\frac{1}{x^{4}}=34$, what is the value of $x^{3}-\frac{1}{x^{3}} $?
Option 2: 6
Option 3: 8
Option 4: 14
Question : If $x+5+\frac{1}{x+1}=6$, then the value of $(x+1)^{3}+\frac{1}{(x+1)^{3}}$ is:
Option 1: 2
Option 2: 0
Option 3: –2
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