Dear Ramakrishna,

Given i=241.25 A

         Volume= 125 mL

         Molarity= 1M

According to Faraday's first law of electrolysis,      w= z*i*t

where,     w is the mass of metal deposited on the electrode

               i is the current passed

               t is the time taken

               z is the electrochemical equivalent of the metal.

In this problem, the metal is silver.

Molarity= (Weight of metal/Molecular weight)/Vol(L)

          1 = (w/108)*1000/125

          108=w*8

           w= 13.5 g.

           Charge passed= it= 241.25*t

           Equivalents of charge= 241.25t/96500

           Equivalent weight= 13.5*96500/241.25t

                                     = 5400/t

          108=5400/t

           t= 50 s.

Dear Ramakrishna,

Given i=241.25 A

         Volume= 125 mL

         Molarity= 1M

According to Faraday's first law of electrolysis,      w= z*i*t

where,     w is the mass of metal deposited on the electrode

               i is the current passed

               t is the time taken

               z is the electrochemical equivalent of the metal.

In this problem, the metal is silver.

Molarity= (Weight of metal/Molecular weight)/Vol(L)

          1 = (w/108)*1000/125

          108=w*8

           w= 13.5 g.

           Charge passed= it= 241.25*t

           Equivalents of charge= 241.25t/96500

           Equivalent weight= 13.5*96500/241.25t

                                     = 5400/t

          108=5400/t

           t= 50 s.