Question : What is the value of $\frac{3 \cos 62^{\circ}}{\sin 28^{\circ}}-\frac{2 \tan 34^{\circ}}{\cot 56^{\circ}} ?$
Option 1: 3
Option 2: 1
Option 3: 5
Option 4: 4
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Correct Answer: 1
Solution : We know that $\sin(90^{\circ} - \theta) = \cos \theta$ and $\cot(90^{\circ} - \theta) = \tan \theta$ $\frac{3 \cos 62^{\circ}}{\sin 28^{\circ}}-\frac{2 \tan 34^{\circ}}{\cot 56^{\circ}} $ $=\frac{3 \cos 62^{\circ}}{\sin (90-62)^{\circ}}-\frac{2 \tan 34^{\circ}}{\cot (90-34)^{\circ}} $ $= \frac{3 \cos 62^{\circ}}{\cos 62^{\circ}}-\frac{2 \tan 34^{\circ}}{ \tan 34^{\circ}}$ $=3 - 2 $ $= 1$ Hence, the correct answer is 1.
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Question : The value of $\frac{\operatorname{sin} 58^{\circ}}{\cos 32^{\circ}}+\frac{\sin 55^{\circ} \sec 35^{\circ}}{\tan 5^{\circ} \tan 45^{\circ} \tan 85^{\circ}}$ is equal to:
Option 1: 2
Option 3: 0
Option 4: 3
Question : The value of $\frac{\sin 25^{\circ}\cos 65^{\circ}+\cos 25^{\circ}\sin 65^{\circ}}{\tan ^{2}70^{\circ}-cosec^{2}20^{\circ}}$ is:
Option 1: –1
Option 2: 0
Option 3: 1
Option 4: 2
Question : If $\frac{x-x\tan^{2}30^{\circ}}{1+\tan^{2}30^{\circ}}=\sin^{2}30^{\circ}+4\cot^{2}45^{\circ}-\sec^{2}60^{\circ}$, then value of $x$ is:
Option 1: $\frac{1}{4}$
Option 2: $\frac{1}{5}$
Option 3: $\frac{1}{2}$
Option 4: $\frac{1}{\sqrt3}$
Question : Evaluate the given expression: $\cos ^2 36^{\circ}+\cos 54^{\circ} \cdot \sin 36^{\circ}+\left(\frac{\tan 26^{\circ}}{\cot 64^{\circ}}\right)$
Option 1: 4
Option 2: 3
Question : If $\mathrm{A}=\cot 30^{\circ} \tan 60^{\circ}+\cot 60^{\circ} \tan 30^{\circ}$, then what is the value of A?
Option 1: $\frac{1}{ \sqrt{ 3}}$
Option 2: $\frac{10}{3}$
Option 3: $\frac{10}{ \sqrt{3}}$
Option 4: $\frac{1}{3}$
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