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What is total number of isomers in square planar complex M[(F) (Cl) (SCN) (NO2)] ? asked in jee 2019.


yash 11th Jan, 2019
Answers (2)
Aditya Sorout 28th Dec, 2019

bro,

it has 3 geometrical isomers

no2 and scn are ambedient nucleophile

therefore total isomers are 3*2*2=12

....easy


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yash sarraf 11th Jan, 2019

Hello yash.

For any square planar complex of type MABCD,there are no optical isomers but only geometrical isomers.There will be a total of 3 isomers.The three isomers place A trans to C,A trans to B,and A trans to D.There won't be any chiral isomer because there is always a plane of symmetry present in the square planar complex.Hence,a total of 3 isomers.

2 Comments
Comments (2)
11th Jan, 2019
But the options were a)8 b)12 c)4 d)16
Reply
10th Mar, 2021
Wrong
Reply
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