Hi Priya

40 ml of 0.1 m H2SO4

NaOH dissociates as -

NaOH --> Na+ + OH-

Hence, it will produce

[OH] = 0.2 × 40 / 1000 moles

[OH] = 8×10^-3 moles

So We'll need the same amount of H+ ions to neutralize it.

H2SO4 dissociates as -

H2SO4 --> 2H+ + (SO4)2-

Hence, it will produce

[H+] = 2 × 0.1 × x / 1000

8×10^-3 = 2 × 0.1 × x / 1000

x = 40 ml

Therefore, 40 ml of 0.1 m H2SO4 will be required.

Hope this information will help you. hoping that you will be understanding the solution.

ALL THE BEST