Hello Aspirant,

According to previous year trends in JEE Mains Exam, you can get rank near about 20k to 25k.

JEE Main 2019 result will be announced in online mode by the authorities. As Paper-I will be conducted in multi-shifts, raw marks obtained by the candidates in different sessions will be converted to NTA Score. 

The authorities will merge the calculated NTA scores for all the sessions and will announce the result of JEE Main 2019 for January attempt on January 31. This result will be comprised of four NTA scores for each of the three subjects- Mathematics, Physics, Chemistry along with the total marks obtained in Paper-1 of JEE Main2019 for the first attempt.

The same procedure will be applied to calculate the JEE Main 2019 result for second attempt.

NTA will release the merit list of JEE Main 2019 on April 30 in online mode. There will be a combined rank list of JEE Main 2019 for both the attempts which will mention the details of candidates who will qualify for JEE Advanced 2019. The merit list will be prepared through normalization procedure based on percentile score. The percentile score of a candidate will be the score obtained after using normalization method (instead of the raw marks of the candidate) which will be used for preparation of the merit lists.

The four NTA scores for each of the candidates in Paper-1 for both the first and second attempt will be merged for compilation of result and preparation of overall JEE Main 2019 rank list using the normalization formula. 

For More information you can check the below link:

https://engineering.careers360.com/exams/jee-main

All the best!