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What will be the chances of colleges for me at 98.2 percentile in JEE MAINS 2020(January attempt)? ..And should i prepare for Mains or Advanced?


Rachit Shivliha 31st Jan, 2020
Answers (3)
Rishikesh Shandilya 31st Jan, 2020
Hello Aspirant.
Congratulations for your success

Getting a percentile of 98.2 your expected JEE Main rank can be calculated by using the formula
(100-your percentile)*869010/100
And is found to be 15642 . With this expected rank the chances of getting good NITS IIITS is more .I will suggest you to go for JEE ADVANCE.



Hope this helps you
Good Luck

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Subhodeep Biswas 31st Jan, 2020
Hey there hope you're doing well.
Dear aspirant, according to your percentile score in JEE MAIN examination your expected rank is about 15,642. With this rank you are expected to get into top NITs. For further preparation I would suggest you to prepare for JEE ADVANCED as with this score you can easily get college in any category moreover further revision may increase this score but you need to focus on your advance you need ample time for practising questions with in-depth knowledge.
I'm also providing you with our college predictor link for getting a better picture of the colleges you can get with this percentile.
Link-https://engineering.careers360.com/jee-main-college-predictor.
Thank you hope this helps you!
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priyaankasarkar Student Expert 31st Jan, 2020

You havent mentioned the State and Category you belong to. This is important because the cut offs are different for Home State Candidates and Other State Candidates. So please do help us with those details for relevant information.

Meanwhile, your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 15642. Let's say the number of candidates for April exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 12,00,000/100.

You will qualify for JEE Advanced because the expected qualifying percentile is above 85. Now to predict colleges, please use our college predictor:

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