Question : What will be the net discount (in percentage) after two successive discounts of 50% and 50%?
Option 1: 85%
Option 2: 75%
Option 3: 100%
Option 4: 95%
Correct Answer: 75%
Solution : Given: Both first and second discounts = 50% Net discount = $(x+y-\frac{xy}{100})$%, where $x$ and $y$ are two successive discounts. = $50+50-\frac{\text{50×50}}{100}$ = $100-\frac{\text{2500}}{100}$ = $100-25$ = $75$% Hence, the correct answer is 75%.
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Question : What will be the net discount (in percentage) after the two successive discounts of 40% and 20%?
Option 1: 60%
Option 2: 68%
Option 3: 52%
Option 4: 42%
Question : What will be the net discount (in percent) after giving three successive discounts of 10%, 20%, and 30%?
Option 1: 50.4%
Option 2: 49.6%
Option 3: 45.3%
Option 4: 48.4%
Question : Two successive discounts of 30% and 20% are equivalent to a single discount of:
Option 1: 44%
Option 2: 52%
Option 3: 45%
Option 4: 50%
Question : A supermarket offers the following discount schemes for buyers. I. Two successive discounts of 25% and 15% II. Successive discounts of 35% and 5% III. A discount of 38% Which offer is better for the customer?
Option 1: Either I or III
Option 2: Only I
Option 3: Only II
Option 4: Only III
Question : Three successive discounts 22%, 17% and 11% are equivalent to a single discount of:
Option 1: approximately 42%
Option 2: approximately 25%
Option 3: approximately 50%
Option 4: approximately 45%
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