Question : Which of the following expressions is equal to the expression $\frac{x^2-3 x+2}{x^2-4}$?
Option 1: $\frac{x+1}{x-2}$
Option 2: $\frac{x-1}{x+2}$
Option 3: $\frac{x+1}{x+2}$
Option 4: $\frac{x-1}{x-2}$
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Correct Answer: $\frac{x-1}{x+2}$
Solution : $\frac{x^2-3 x+2}{x^2-4}$ = $\frac{(x-2)(x-1)}{(x-2)(x+2)}$ = $\frac{(x-1)}{(x+2)}$ Hence, the correct answer is $\frac{(x-1)}{(x+2)}$.
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Question : Find the value of the expression $\frac{x^2-1}{x-1}-\frac{x^2-9}{x-3}$.
Option 1: 1
Option 2: –2
Option 3: –1
Option 4: 2
Question : Simplify the given expression. $\frac{x^3+y^3+z^3-3 x y z}{(x-y)^2+(y-z)^2+(z-x)^2}$
Option 1: $\frac{1}{3}(x+y+z)$
Option 2: $(x+y+z)$
Option 3: $\frac{1}{4}(x+y+z)$
Option 4: $\frac{1}{2}(x+y+z)$
Question : The value of $x$ in the expression $\tan^{2}\frac{\pi }{4}-\cos^{2}\frac{\pi }{3}=x\sin\frac{\pi }{4}\cos\frac{\pi }{4}\tan\frac{\pi }{3}$ is:
Option 1: $\frac{2}{\sqrt{3}}$
Option 2: $\frac{3\sqrt{3}}{4}$
Option 3: $\frac{1}{\sqrt{3}}$
Option 4: $\frac{\sqrt{3}}{2}$
Question : If $x+\frac{1}{x}=3$, then the value of $\frac{3x^{2}-4x+3}{x^{2}-x+1}$ is:
Option 1: $\frac{4}{3}$
Option 2: $\frac{3}{2}$
Option 3: $\frac{5}{2}$
Option 4: $\frac{5}{3}$
Question : The 12th term of the series $\frac{1}{x}+\frac{x+1}{x}+\frac{2x+1}{x}+...$ is:
Option 1: $\frac{11x+1}{x}$
Option 2: $\frac{12x+1}{x}$
Option 3: $\frac{x+12}{x}$
Option 4: $\frac{x+11}{x}$
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