Which of the following has maximum number of molecules ? a. 7 g N2 b. 2 g H2 c. 8 g O2 d.20 g NO2
Hello Gaikwadomkar,
As we know to find maximum number of molecules we have to divide the given mass by its molar mass to get moles, then multiply times 6.022×1023 molecules1 mol
Now to answer your question 1 mole of any element contain 6.023 x 1023 number of molecules.
1 g mole of N2 = 28 g N2 => 7 g N2 = 0.25 g mole N2
1 g mole of O2 = 32 g O2 => 16 g of O2 = 0.5 g mole O2
1 g mole of H2 = 2 g H2 => 2 g H2 = 1.0 g mole H2
1 g mole NO2 = 14 + 16 x 2 = 46 => 16 g of NO2 = 0.35 mole NO2
2 g H2 (1 g mole H2) contain maximum molecules.
hope this will help you a lot.
thank you.
Hello
The correct option is b) 2g H2
EXPLANATION
we know that,
No. of moles is given by
= Molecular weight (M)/ given Weight (W)
Therefore,
(a) No. of moles in a option =7 /28= 0.25 moles
(b) No. of moles in b option i.e H2=2/2 = 1 mole
(c) No. of moles in c option =16 /46= 0.347 moles
(d) No. of moles in D option =16 /32= 0.5 moles
Now as H2 has maximum no. of moles, thus it has maximum no. of molecules
Thank you