Question : Which of the number among 9592450, 9592330, 9592885 and 9592741 is divisible by 11?
Option 1: 9592885
Option 2: 9592741
Option 3: 9592450
Option 4: 9592330
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Correct Answer: 9592330
Solution : If the difference between the sum of its digits at odd places and the sum of its digits at even places is either 0 or a number divisible by 11, then the given number is divisible by 11. (a) For 9592450 = (9 + 9 + 4 + 0) – (5 + 2 + 5) = 22 – 12 = 10 (b) For 9592330 = (9 + 9 + 3 + 0) – (5 + 2 + 3) = 21 – 10 = 11 (c) For 9592885 = (9 + 9 + 8 + 5) – (5 + 2 + 8) = 31 – 15 = 16 (d) For 9592741 = (9 + 9 + 7 + 1) – (5 + 2 + 4) = 26 – 11 = 15 Hence, the correct answer is 9592330.
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Option 2: 1
Option 3: 2
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Option 3: 12
Option 4: 9
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Option 3: 5
Option 4: 4
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Option 3: 16
Option 4: 8
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