With an SC category rank of 12,829 in JEE Main 2025 and Telangana as your home state, securing a seat in top NITs or IIITs for Computer Science Engineering (CSE) may be challenging. However, you still have opportunities in newer NITs, IIITs, and GFTIs, especially if you're open to branches like Electronics and Communication Engineering (ECE), Mechanical Engineering, or Civil Engineering.

Potential Options:

NITs:

• NIT Nagaland

• NIT Mizoram

• NIT Arunachal Pradesh

• NIT Meghalaya

IIITs:

• IIIT Bhagalpur

• IIIT Kalyani

• IIIT Ranchi

• IIIT Manipur

GFTIs:

• Assam University, Silchar

• Birla Institute of Technology, Mesra

• Gurukula Kangri Vishwavidyalaya, Haridwar

These institutes have previously admitted SC category candidates with ranks similar to yours. It's advisable to participate actively in JoSAA counselling, consider all available rounds, and be flexible with branch preferences to maximize your chances. Stay positive and explore all options to find the best fit for your engineering aspirations!

With 49.8 percentile (approx. 7–8 lakh rank) in JEE Mains under the General category, getting into NITs, IIITs, or GFTIs through JoSAA is unlikely. But don’t worry — you still have good options:

• Apply through your state counselling (like TS EAMCET or others).

• Look into private universities like LPU, SRM, Amity, Chandigarh University, or Jain University.

• Some colleges offer direct admission or management quota seats based on Class 12 scores.

Stay confident and aim for colleges that offer strong placement and faculty support!

A rank of 109,000 in JEE Mains may not be sufficient to secure a seat in top NITs, especially for popular branches like Computer Science Engineering (CSE) or Electronics. However, you still have chances in newer NITs , IIITs , and GFTIs , especially for other branches like Mechanical, Civil, or Electrical Engineering.

Some possible options include:

• NIT Agartala

• NIT Puducherry

• NIT Nagaland

• IIIT Kalyani

• GFTIs like BIT Mesra

Keep an eye on the JoSAA counselling process and be flexible with branch choices to improve your chances!

With a CRL rank of 347,728 in JEE Mains, it will be very difficult to secure a Computer Science (CS) seat in top colleges in Mumbai, as these institutes typically have very high cut-offs for CS. However, you might still have a chance in some private or lesser-known engineering colleges with lower cut-offs. Colleges like Ajeenkya DY Patil University, Dr. D.Y. Patil College of Engineering, and Thakur College of Engineering could be potential options. Checking the specific cut-offs and using a college predictor tool will help you get a clearer idea.

For more details you can visit the link given below

https://engineering.careers360.com/jee-main-college-predictor

For 77 marks in JEE Main Session 2 2025, an OBC-NCL candidate is expected to be in the range of 90,000 to 169,542 rank. This translates to a percentile range of 90-92.

The actual rank and percentile can vary depending on the difficulty level of the exam paper and the total number of candidates who appeared in this attempt.

To determine your KCET rank, the Karnataka Examinations Authority (KEA) considers 50% of your board exam marks (in Physics, Chemistry, and Mathematics) and 50% of your KCET marks.

Here's how the calculation works:

1. Calculate your board exam percentage in PCM: You scored 92% in boards (assuming this is the average of your Physics, Chemistry, and Mathematics marks).

2. Calculate your KCET percentage: You scored 94 out of 180 in KCET. Percentage = (94 / 180) * 100 = 52.22% (approximately)

3. Calculate your CET score: CET Score = (50% of Board Percentage) + (50% of KCET Percentage) CET Score = (0.50 * 92) + (0.50 * 52.22) CET Score = 46 + 26.11 CET Score = 72.11

Now, to estimate your rank based on this CET score, we need to look at previous years' trends of KCET marks vs. rank. Keep in mind that these trends can vary slightly each year depending on the overall performance of all candidates and the difficulty level of the exam.

Based on the previous year's data and available rank predictors, a CET score around 72 could potentially place you in the rank range of approximately 15,001 to 25,000 .

I hope this helps.

To estimate your KCET rank, we need to consider both your KCET score (66 out of 180) and your board exam marks (280 out of 300). The Karnataka Examinations Authority (KEA) gives equal weightage (50%) to both these scores to determine your CET score, which is then used to assign the rank.

Here's how to calculate your estimated CET score:

1. Calculate your board exam percentage in PCM: Assuming the 280 out of 300 is the total of your marks in Physics, Chemistry, and Mathematics, your percentage in PCM is: (280 / 300) * 100 = 93.33% (approximately)

2. Calculate your KCET percentage: Your KCET score is 66 out of 180. Percentage = (66 / 180) * 100 = 36.67% (approximately)

3. Calculate your CET score: CET Score = (50% of Board Percentage) + (50% of KCET Percentage) CET Score = (0.50 * 93.33) + (0.50 * 36.67) CET Score = 46.665 + 18.335 CET Score = 65

Now, to estimate your rank based on this CET score, we need to look at previous years' trends of KCET marks vs. rank. Keep in mind that these trends can vary slightly each year.

Based on the previous year's data and available rank predictors, a CET score around 65 could potentially place you in the rank range of approximately 40,001 to 60,000 .

I hope this helps.

To secure a rank below 5000 in the AP EAMCET, a focused and strategic preparation is essential. Firstly, thoroughly understand the syllabus and exam pattern . The exam primarily covers Physics, Chemistry, and Mathematics from your 11th and 12th-grade curriculum of the Board of Intermediate Education of Andhra Pradesh. Familiarize yourself with the weightage of different topics to prioritize your study plan.

Create a realistic and consistent timetable . Allocate sufficient time to each subject based on your strengths and weaknesses. Regular study sessions with short breaks are more effective than long, tiring ones. Ensure you dedicate time for revision as well.

Focus on conceptual clarity . Instead of rote learning, aim to understand the fundamental principles behind each concept. This will help you tackle a wider range of problems. Practice problem-solving regularly. Solve numerical problems and objective-type questions from textbooks and previous years' question papers.

Previous years' question papers are invaluable resources. Solving them will give you an idea of the exam's difficulty level, the types of questions asked, and the important topics. It will also help you improve your speed and accuracy.

Take mock tests regularly. Simulate the actual exam environment to assess your preparation level and identify your weak areas. Analyze your performance in these tests and focus on improving your scores in subsequent attempts.

Ensure you have the right study material . Stick to standard textbooks and reliable online resources. Avoid getting overwhelmed by too many books. NCERT books are a good starting point.

Maintain a healthy lifestyle . Get enough sleep, eat nutritious food, and exercise regularly to keep your mind and body in optimal condition for studying. Stay positive and avoid stress. Consistent effort and a well-planned strategy will significantly increase your chances of achieving a rank below 5000 in AP EAMCET.

I hope this helps.

To estimate your KCET rank, both your board exam marks and your KCET exam marks are considered with equal weightage (50:50).

First, we need to calculate your percentage in both exams for the relevant subjects (Physics, Chemistry, and Mathematics, assuming you are aiming for engineering).

Your board marks are 284 out of 300. So, your board percentage is: (284 / 300) * 100 = 94.67%

Your KCET marks are 80 out of 180. So, your KCET percentage is: (80 / 180) * 100 = 44.44%

Now, to calculate your CET rank determining score, we take 50% of each percentage and add them together: CET score = (50% of Board Percentage) + (50% of KCET Percentage) CET score = (0.50 * 94.67) + (0.50 * 44.44) CET score = 47.335 + 22.22 CET score = 69.555

Based on previous year's trends and available data, a KCET score around 70 often corresponds to a rank somewhere in the range of 40,001 to 50,000 or even higher .

However, it's crucial to understand that this is just an estimate based on previous year's data and the general trend. The actual rank can vary depending on factors such as the overall performance of all candidates, the difficulty level of the exam this year, and the normalization process if applicable to different boards.

For a more precise prediction, you might want to use online KCET rank predictor tools that take into account the 50:50 weightage and attempt to correlate scores with likely ranks based on past data. Once the official KCET results are released, you will get your actual rank.

I hope this helps.