See as you are in sort of interdisciplinary field i.e., you do the data management and software development for the purpose of telecommunication then you should mention IT because you are not directly involved in Telecommunication as it would have been the case for any Electronics and Communication Engineer. So

Hello Candidate,

The number of gram equivalents of solute is equal to the weight of solute added divided by the molar mass of solute or salt solution. The molar mass of NaCl is equal to 58.5, so the gram equivalent of solute is equal to 58.5/58.5= 1.

The volume of

Dear student,

Here, mass of solute is = 12.5 g

Volume of solvent is = 250 ml = 0.25 L

Now, Concentration = mass of solute in g / volume of solution in L

= 12.5 / 0.25 = 125*100/25*10

Hence Conc. = 50g/L

Hope this helps.

Hi

Since 2 moles of KClO3 yields 2 moles of KCl and 3 moles of O2

Therefore, the mole ratio for the reaction is 2:2:1

According to the information provided in the question,

By using ideal gas law, 22.4l = 1 mole

Then, 6.72l= 1×6.72/22.4 = 0.3 moles

As per

Hi, here I'm providing the answer for your question.

The formula to find molarity is, M= n/v

Where, M=molar concentration

n= moles of solute

v= litres of solution

4% (w/v) means 4gm of NaOH in 100ml

The molecular mass of NaOH is = 40

So molarity=4/40 * 1000/100 = 1M.