See as you are in sort of interdisciplinary field i.e., you do the data management and software development for the purpose of telecommunication then you should mention IT because you are not directly involved in Telecommunication as it would have been the case for any Electronics and Communication Engineer. So the wiser way would be to mention both or you may mentioned Telecommunication (Your job description in short).

I hope this answer helps. All the very best for your future endeavors!

Hello Candidate,

The number of gram equivalents of solute is equal to the weight of solute added divided by the molar mass of solute or salt solution. The molar mass of NaCl is equal to 58.5, so the gram equivalent of solute is equal to 58.5/58.5= 1.

The volume of solvent is equal to 500ml or can be expressed as 0.5 litres. So, the formula of normality is equal to gram equivalent of solute / the volume of solvent in litres which is equal to 1/0.5= 2 Normal

Hope you found it helpful. If you have any further queries feel free to post it here!!

Dear student,

Here, mass of solute is = 12.5 g

Volume of solvent is = 250 ml = 0.25 L

Now, Concentration = mass of solute in g / volume of solution in L

= 12.5 / 0.25 = 125*100/25*10

Hence Conc. = 50g/L

Hope this helps.

Hi

Since 2 moles of KClO3 yields 2 moles of KCl and 3 moles of O2

Therefore, the mole ratio for the reaction is 2:2:1

According to the information provided in the question,

By using ideal gas law, 22.4l = 1 mole

Then, 6.72l= 1×6.72/22.4 = 0.3 moles

As per the mole ratio, 0.3 moles of oxygen to be liberated, we need 0.3×2=0.6 moles of KClO3

Moles= mass/molar mass

Molar mass of potassium chlorate is 122.5g/mol that is given and moles is 0.6

Hence, mass of KClO3 required = 122.5g/mol×0.6 moles = 73.5g

Thank you

Hi, here I'm providing the answer for your question.

The formula to find molarity is, M= n/v

Where, M=molar concentration

n= moles of solute

v= litres of solution

4% (w/v) means 4gm of NaOH in 100ml

The molecular mass of NaOH is = 40

So molarity=4/40 * 1000/100 = 1M.

Therefore, the molarity is 1.0m