Acting
Hello Aspirant,
After your 12th, You can do short term, certificate courses, graduation courses in arts and drama. Get some experience in theater side by side. You can build your acting skills with small competitions in college and add it later to your experience.
You can join any Drama classes. Drama classes can introduce students to performing, different methods and schools of thought in acting, writing their own material, and different approaches to characters, along with stage and costume design.
Good Luck!
Hi Aspirant,
If you are interested in pursuing a career in the acting field, you can do a Diploma in Acting course after your 10th standard. Here are the top colleges offering this course in India with their total fees:
Hello Shweta,
B.A in acting is a 3 years undergraduate course in India. Firstly, the career in acting mostly depends upon your interest and skills. If a candidate has completed his graduation in acting, then it gives a chance to candidate to build up abilities and credits to perform unique creative works in the zones of theater.
The eligibility criteria for this course is that the candidate should have completed his / her 10 + 2 with a minimum aggregate of 50%
The best colleges offering courses in B.A acting are:
1. Film and Television Institute of India, Pune
2. National School of Drama, Delhi
3. Asian Academy of Film and Television
4. Kurukshetra University
5. Whristling Woods International, Mumbai
Best Wishes.
Hello Shweta!
Hope you are doing great in your life!
I would like to give the names of some acting related courses which can help you in future to build your career in acting below:-
These are the things that will help you to enhance your career in acting industry so keep working hard keep growing.
All the best for your future!
Thanks.
Your similar kind of query already has been answered, You can check the answer to go through with the given below link.
https://www.careers360.com/question-acting-course-admission-process
You can join any Drama classes. Drama classes can introduce students to performing, different methods and schools of thought in acting, writing their own material, and different approaches to characters, along with stage and costume design. The admission process varies college to college.
Here are some of the colleges you can prefer for learning Acting.
FILM AND TELEVISION INSTITUTE OF INDIA (FTII), PUNE
BARRY JOHN ACTING STUDIO, MUMBAI
NATIONAL SCHOOL OF DRAMA (NSD), NEW DELHI
INSTITUTE OF CREATIVE EXCELLENCE, MUMBAI
WHISTLING WOODS INTERNATIONAL, MUMBAI
Gaurav ;
According to D'Alembert , a fictional force or a pseudo force acts in a direction opposite to that of the motion of the free body. It amounts up as an amount of it's mass multiplied by it's acceleration.
So, in this case the mass of the freely falling body is 20 kg and the acceleration is 6m per sec² . So, the fictional force will be 20*6 = 120 N .
Hope you got your answer!
Hello Sree Vardhan,
You may use the concepts of laws of floatation to solve this fluids problem.
Consider mass of the body =m
therefore weight of the body = mg
Now let σ be the density of the object and ρ is the density of the water and V is the volume of the object.
So weight = mg = Vσg
and buoyant force = Vρg
bf=n×weight= Vρg=n*Vσg= σ /ρ = 1/n.
( Specific gravity = density of object /density of water.)
Hence, answer is 1/n.
Hope this helps
Regards
Every career path comes with its own perks. With technology ever evolving and crime evolving too, law needs to be always guarded and you will never run of opportunities in Legal field if you are talented enough. Journalism is good as long as you do not limit yourself to paparazzi culture but evolve beyond that. Acting is a strange field. It has its opportunities. The celebrity news that we read is the tip of the ice berg. What goes unsaid is the no.of people who aspire to be actors and the no.of people who really become one. Not every one can pull of a Karthik Aryan stunt. This is no means trying to pull your spirits down but this is the fact.
The resultant will be a vector. So it is a tail of force on top and end on the head of the horizontal force. It is clear that the two forces and the resultant will form an equilateral triangle. So the resultant will be 10 dyne force acting on a line that makes 60 degree downwards angle with the horizontal.
If two forces are placed on adjacent sides of a parallelogram, the angle between them would be 120 degrees.
Now using the law of parallelogram we get
R = √10^2 + 10^2 + 2 x 10 x 10 x cos 120
R = √ 100 (cos 120 = - 1/2)
R = 10
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