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for a body of mass 50kg the velocity time graph is shown in fig. the force acting on the body is

ADITYA KUMAR Student Expert 1st Oct, 2019

Hello there!

Greetings!

Slope under (v-t) curve gives acceleration but since you haven't provided the diagram so if I assume
a = 0.5m/s
Then,Force = m a
=50 *0.5=25N.

thankyou

Good luck

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two forces f1=2i-5j-6k and f2=-i+2j-k are acting on a boby at points (1,1,0) and (0,1,2) respectively. Find torque acting on body about point (-1,0,1)

Abhishek Roy Student Expert 28th Sep, 2019

Hey!There

First find torque due to force F1 about required point..And then torque due to force F2 about same point.Then take vector addition of these two torque..

Ask if any query..

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