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Question : Directions: In a certain code, if AMOUNT is written as BNPTMS, how is AROUND written in that code?
Option 1: BSPUNT
Option 2: BSUPTN
Option 3: BSPTMC
Option 4: ZSPVOE
Correct Answer: BSPTMC
Solution : Given: AMOUNT is written as BNPTMS.
Divide the letters of the word into two halves. Then, add one to the place values of the first half and subtract one from the place value of the second half of the letters of the given words.
Question : Select the option that expresses the given sentence in direct speech.
I warned Rita not to be late the next day.
Option 1: I warned to Rita, “Don’t be late tomorrow”.
Option 2: I warning Rita, “Not be late tomorrow”.
Option 3: I warned Rita, “Not be late tomorrow”.
Option 4: I warned Rita, “Don’t be late tomorrow”.
Correct Answer: I warned Rita, “Don’t be late tomorrow”.
Solution : The correct choice is the fourth option.
Narration Conversion:
Question : A, B and C were partners in a firm sharing profits in a 3: 3: 2 ratio. They admitted D as a new partner for 4/7 profit. D acquired his share 2/7 from A, 1 / 7 from B and 1 / 7 from C. The new profit sharing ratio will be
Option 1: 5:13:6:32
Option 2: 5:13:6:4
Option 3: 3: 3: 2: 4
Option 4: None of the above
Correct Answer: 5:13:6:32
Solution : Answer = 5:13:6:32 A's share $=\frac{3}{8}-\frac{2}{7}=\frac{21-16}{56}=\frac{5}{56}$ B's share $=\frac{3}{8}-\frac{1}{7}=\frac{21-8}{56}=\frac{13}{56}$ C's share $=\frac{2}{8}-\frac{1}{7}=\frac{14-8}{56}=\frac{6}{56}$ D s share $=\frac{4}{7}$ Thus, the new profit-sharing ratio for A, B, C and D will be : $\frac{5}{56}: \frac{13}{56}: \frac{6}{56}: \frac{4}{7} \text { or } \frac{5: 13: 6: 32}{56} \text { or
Question : A cuboid with sides 4, 6, and 8 units is covered with paper. The paper is removed and a square is made from it. What is the side (in units) of the square?
Option 1: 12.24
Option 2: 16.62
Option 3: 14.42
Option 4: 12.62
Correct Answer: 14.42
Solution : The total surface area of cuboid $= 2(lb+bh+hl)$ where $l$ is the length, $b$ is the breadth, and $h$ is the height of the cuboid. Area of square = $(\text{side})^2$ According to the question, The paper used for covering the cuboid is removed and a
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